Question

.. Prove that (1+ tan + coto) (sin - cos 0)
sece
cosece
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Answer 1

Answer:

$= (1 + tan + cot0)(sin - cos0)$

$= (1 + tan + cot)(sin - 1)$

$= (tan + cot = 1)(sin - cos = 1)$

$= (tan + tan = 1)(sin - sin = 1)$

$= (2tan = 1)(0 = 1)$

$= (tan = \frac{1}{2} )(0)$

$tan = \frac{1}{2} \times 0$

$tan = 0$