Prove
that
1+tan square A / 1+cos square A = (1-tan square A / 1-cot A) hole square = tan square A
Answers
Answered by
1
Step-by-step explanation:
answer as shown above .........
Attachments:
Answered by
1
LHS = tan²A - sin²A
= ( sin²A/cos²A ) - sin²A
= sin²A [ 1/cos²A - 1 ]
= sin²A( sec²A - 1 )
= sin²A tan²A
[ since , sec²A - 1 = tan²A ]
= tan²Asin²A
= RHS
Similar questions