Math, asked by vuyyurusoujanya1983, 10 months ago

Prove
that
1+tan square A / 1+cos square A = (1-tan square A / 1-cot A) hole square = tan square A​

Answers

Answered by kiran12355
1

Step-by-step explanation:

answer as shown above .........

Attachments:
Answered by Anonymous
1

LHS = tan²A - sin²A

= ( sin²A/cos²A ) - sin²A

= sin²A [ 1/cos²A - 1 ]

= sin²A( sec²A - 1 )

= sin²A tan²A

[ since , sec²A - 1 = tan²A ]

= tan²Asin²A

= RHS

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