Question

Prove that (1+ tan square tita) (1-sin tita) (1+sin tita) =1​

Answer 1

Step-by-step explanation:

see the pic it will clear your dout

Answer 2

Step-by-step explanation:

$\sf{first\:we\:do\:step\:by\:step}$

$\sf{1 + tan^2\theta = 1 + \frac{sin^2\theta}{cos^2\theta} = \frac{sin^2\theta + cos^2\theta}{cos^2\theta} = \frac{1}{cos^2\theta} }$

$\sf{we\:know\:that\: = (a + b)(a - b) = a^2 - b^2}$

$\sf{(1 - sin\theta)(1 + sin\theta) = 1 - sin^2\theta = cos^2\theta}$

$\sf{then\:(1 + tan^2\theta)(1 - sin^2\theta)(1 + sin^2) = \frac{\cancel{cos^2\theta}}{\cancel{cos^2\theta}} } = 1$