prove that (1+tan theta+sec theta)(1+ tan theta- sec theta) = 2
Answers
Answered by
0
Answer:
L.H.S =
secθ−1
tanθ
+
secθ+1
tanθ
=
(secθ−1)(secθ+1)
tanθ[secθ+1+secθ−1]
=
sec
2
θ−1
2tanθ.secθ
=
tan
2
θ
2tanθ.secθ
=
tanθ
2secθ
=
cosθ
sinθ
2
cosθ
1
=
sinθ
2
=2 cosecθ
= R.H.S
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