Question

Prove that : ( 1 + tan²θ ) ( 1 + sin²θ ) ( 1 - sinθ ) = 1​

Answer 1

Answer:

(1+tan

2

θ)(1+sinθ)(1−sinθ)

=sec

2

θ(1−sin

2

θ)

=sec

2

θ×cos

2

θ

=

cos

2

θ

1

×cos

2

θ

=1