Question

Prove that:-1 +tan2A=sec2A​

Answer 1

Answer:

OK

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Step-by-step explanation:

$1 + {tan}^{2} = {sec}^{2} \\ = 1 + \frac{ {sin}^{2} }{ {cos}^{2} }..........(tan = \frac{sin}{cos} ) \\ = \frac{ {cos }^{2}+ {sin}^{2} }{cos {}^{2} } .............lcm \\ = \frac{1}{cos {}^{2} } .......... {sin}^{2} + {cos}^{2} = 1 \\ = sec {}^{2} \\ hence \: proved$