prove that (1+tan²A)sinA.cosA=tanA
Answers
Answered by
3
Answer:
WE KNOW
LHS= (1+tan^2A)× sinA .CosA
NOW
= sec^2A×AsinA .cosA
= 1/cos^2A×cosAsinA
= sinA/cosA
= tanA [RHS]
HENCE PROVED
Answered by
2
Answer:
Here, LHS...
(1+tan2A)sinA.cosA
= (1+sin2A/cos2A)sinA.cosA
= (cos2A+sin2A/cos2A)sinA.cosA
= 1/cos2A*sinA.cosA
= 1/cosA*sinA
= sinA/cosA
= tan =RHS....
Hence proved.....
Hope this helps u.....
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