Prove that:
[1-tanA/1-CotA]^2= tan^2A
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Step-by-step explanation:
(1-tanA)square / (1-cotA) square
(1-tanA) square / [(tanA - 1)/ tanA)] square
(1-tanA) square / [(tanA - 1)sq / tan sq A]
(1-tanA)sq / [(1-tanA) sq / tan sq A]
Tan sq A
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