prove that 1-tanA/1+tanA=cotA-1/cotA+1
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Step-by-step explanation:
on lhs
1-tanA/1+tanA
(1 - sinA/cosA) / (1+ sinA/cosA)
(cosA - sinA)/cosA / (sin A + cosA)/cosA
cosA - sinA/sin A + cosA ........ LHS
now on RHS
cotA-1/cotA+1
(cosA /sinA -1 )/ (cosA /sinA+1)
(cosA -sinA)/sinA / (cosA + sin A)/sin A
(cosA -sinA)/(cosA + sin A) .......... RHS
therefore lhs = rhs
hence proved
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