prove that (1+tanA)^2 + (1+cotA)^2 = (secA+cosecA)
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Answer:
sec²A+cosec²A-(2tanA+2cotA)=sec²A+cosec²A -(2 x secA x cosecA)
2(tanA+cotA)=2xsecAxcosecA
tanA+cotA=secA x cosecA
hope it helps,
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