Math, asked by unnati5959, 1 month ago

Prove that:-
1+tanA/sinA + 1+cotA/cosA = 2(secA + cosecA)

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Answered by 07poonamstar
1

Answer:

we know that

tanA = sinA/cosA and cotA = cosA/sinA

now

1+sina/cosa/sina + 1 + cosa / sina / cosa

cosa + sina / cosa / sina + sina+cosa/sina/cosa

cosa+sina/cosa*sina + sina+cosa / cosa sina

cosa +sina + cosa + sina / cosa *sina

2cosa + 2 sina / cosa* sina

2cosa/cosa*sina +2sina /cosa*sina

2/sina + 2/cosa

we know that 1/sina= coseca , 1/cosa = seca

2coseca + 2seca

2 (coseca + seca)

hence proved

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