Question

prove that (1+w^2)^3=-1​

Answer 1

Answer:

LHS

(1+w^2)^3

$1 + {w}^{6} + 3 \times {w}^{2} +3 \times {w}^{4}$

$1 + 1 + 3 \times {w}^{2} +3 \times {w}$

$1 + 1 + 3 \times ( {w}^{2} + {w})$

= 1 + 1 + 3×( -1 )

= 1+1-3

= -1

=RHS

Hence proved