prove that (1+w)^3-(1+w^2)^3=0
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Answer:
w= 0.0000 - 1.7321 i
w= 0.0000 + 1.7321 i
w =(-1-√-3)/2=(-1-i√ 3 )/2= -0.5000-0.8660i
w =(-1+√-3)/2=(-1+i√ 3 )/2= -0.5000+0.8660i
w = 1
w = 0
Step-by-step explanation:
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