Question

prove that
(1+w)³-(1+w²)³ =0​

Answer 1

Answer:

Step-by-step explanation:

(1+w)³-(1-w²)³=0 factorise using 1-w²=(1-w)(!+w)  

(1+w)³-(1-w)³(1+w)³=0 factorise again  

(1+w)³(1-(1-w)³)=0 so,  

(1+w)³=0 yielding w=-1  

OR  

(1-(1-w)³)=0, yieldin  

1=(1-w)³ i.e w=0

Answer 2

Answer:

(1+w)³ − (1+w²)³

= (1 + w− 1 − w²)[(1 + w)² + (1+ w)(1+w²)+(1+w²)²]

= (w − w²)[1 + w² + 2w +1+w² +w+ w³ +1+wª+2w²]

= (w = w²) [4+4w + 4w²]

= (w - w²) x 0

= 0