Prove that (1+x) n >= (1+nx) ,for all natural numbers n, where x > 1-
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N = {0, 1, 2, 3, ...} where N is natural num
(1+x)n >= (1+nx) for every N- {0}
n +nx >= 1 +nx
n - 1 >= 0 which is true for all +ve natural numbers except 0
(1+x)n >= (1+nx) for every N- {0}
n +nx >= 1 +nx
n - 1 >= 0 which is true for all +ve natural numbers except 0
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