Prove that
[ 1 x yz
1 y zx
1 z xy] =(x-y) (y-z) (z-x)
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Answer:
Multiply the first row by x, second by y , third by z TO GET
[ x x² xyz
y y² xyz
z z² xyz]
TAKE xyz common from 3rd Coloum
IT WILL RESULT IN A SIMPLE PROPERTY OF DETERMINANT
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