Prove that -10,-6,-2,2 is an AP
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2
a1=-10
a2=-6
a3=-2
To be in A.P
a2-a1=a3-a2
4=4
hence proved terms are in A.P
a2=-6
a3=-2
To be in A.P
a2-a1=a3-a2
4=4
hence proved terms are in A.P
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2-(-2)=4
-2-(-6)=4
-6-(-10)=4
We get that difference is same that is 4 now we have a common difference and hence its an ap
-2-(-6)=4
-6-(-10)=4
We get that difference is same that is 4 now we have a common difference and hence its an ap
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