Question

prove that 100-100/100-100=2,0,1

Answer 1

(100-100)/(100-100)= (10^2-10^2)/10(10-10)=(10-10)(10+10)/10(10-10)=2
(100)-(100)/(100-100)=0/0 = indeterminant form it never gives 0 but i am sure if i use limits it will be zero because finite/infinite gives zero
(100-100)/(100-100)=1

Answer 2

All the mathematical operation is done according to the rule of BODMAS.
B=Bracket
O=Of
D=Division
M=Multiplication
A=Addition
S=Subtraction.

THE GIVEN QUESTION:

# PROVING : 100-100/100-100 =1
Here we can either do division first or subtraction first,but according to BODMAS rule, we have to apply Division first.

Since numerator and denominator are same,division will give us the value 1.

So the answer is ⇒ 1

# PROVING:100-100/100-100=2
100 can be written as 10² in the numerator

we get 10²-10²/100-100
             (10-10)(10+10)/10(10-10)               [a²-b²= (a+b)(a-b)]

canceling 10-10 form both numerator and denominator.we get:

(10+10)/10=20/10=2

Hence we get the answer as ⇒2

# Proving 100-100/100-100=0 [Though its against the BODMAS rule,but since you have asked]

100-100/100-100
0/0=0                           [100-100=0]
The answer is ⇒0