prove that 100-100/100-100=2
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in order to prove this
we know that square of 10 is hundred
in this question
100-100/100-100
=(10)^2-(10)^2/(10)^2-(10)^2
from property of a^2-b^2
=(10+10)(10-10)/(10+10)(10-10)
cutting (10-10) in numerator and denominator
=20/20=1
baaki nhi pta bhai!
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