Math, asked by rk521528, 1 year ago

prove that:-
(100-100)/(100-100)=2

Answers

Answered by HridayAg0102

Heya .........

(100-100) / (100- 100) cannot be 2

because 0/0 = 0.

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HOPE IT WILL HELP YOU! ! !

siddhartharao77: Given (100-100)/(100-100) can be written as

(10^2-10^2)/10(10-10)

a^2 - b^2 = (a+b)(a-b)

(10 + 10)(10-10)/10 (10-10)

(10+10)/10

20/10

2

adarshhoax: but there is only "a" not "b"

siddhartharao77: where is a?

adarshhoax: oh the formula is for (a^2)-(b^2)

adarshhoax: not for ( a^2) -(a^2)

siddhartharao77: We have to assume that

adarshhoax: oh you are not understanding

siddhartharao77: Okk..Leave it Adarsh

adarshhoax: as you wish

adarshhoax: you win

Answered by siddhartharao77

Given (100 - 100)/(100 - 100) can be written as

(10^2 - 10^2)/10(10-10)

We know that a^2 - b^2 = (a+b)(a-b)

(10 + 10)(10-10)/10(10 - 10)

(10 + 10)/10

20/10

2.

Hope this helps!

HridayAg0102: but u cannot use this identity for same digits

siddhartharao77: We can use it bro

HridayAg0102: no we can't

HridayAg0102: as

HridayAg0102: if u ll take any square number

HridayAg0102: u will get it 2

HridayAg0102: which is not right

HridayAg0102: maybe this question is wrong

siddhartharao77: Okk..Not all. But this rule won't apply to most of the integers.

HridayAg0102: ok

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prove that:- (100-100)/(100-100)=2

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prove that:-
(100-100)/(100-100)=2