Question

Prove that 100 - 100 upon 100 - 100 = 2​

Answer 1

Answer:

We can write 100 as 10^2. So, (100-100)=(10^2 - 10^2) in the numerator. In the denominator, we can write 100–100 = 10 * (10–10). So, that will make (100–100)/(100–100) = (10^2 – 10^2)/ [10 * (10–10)].

Answer 2

$\mathfrak{dear\;user }$

$\mathfrak{question-}$prove 100-100/100-100=2 ​

$\mathfrak{here\:is\:the\:solution\:for \:the question }$

$a^{2}-b^{2} =(a+b)(a-b)$

$= (100-100)\div (100-100)=2$

$L.H.S$

=$(10^{2} -10^{2})\div10(10-10)$

=$(10+10)(10-10)\div10(10-10)$ $cancel$$(10-10)$$from \:numerator \:and \:denominatior.$

=$10+10\div10$

=$20 \div 10$

$=2$

$R.H.S=2$

$\mathcal{MY\:EXPECTATION\: FOR \:THIS \: ANSWER \:IS }10\:thanks\:and \:brainlist$

$\mathcal{BY \:ROSHAN\: A \:USER \: OF \: BRAINLY}$

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