prove that 1000001235678957° =1
Answers
Answer:
We know that the distance between the two points (x
1
,y
1
) and (x
2
,y
2
) is
d=
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
Let the given vertices be A=(−5,−3), B=(1,−11), C=(7,−6) and D=(1,2)
We first find the distance between A=(−5,−3) and B=(1,−11) as follows:
AB=
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
=
(1−(−5))
2
+(−11−(−3))
2
=
(1+5)
2
+(−11+3)
2
=
6
2
+(−8)
2
=
36+64
=
100
=10
Similarly, the distance between B=(1,−11) and C=(7,−6) is:
BC=
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
=
(7−1)
2
+(−6−(−11))
2
=
6
2
+(−6+11)
2
=
6
2
+5
2
=
36+25
=
61
Now, the distance between C=(7,−6) and D=(1,2) is:
CD=
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
=
(1−7)
2
+(2−(−6))
2
=
(−6)
2
+(2+6)
2
=
(−6)
2
+8
2
=
36+64
=
100
=10
Now, the distance between D=(1,2) and A=(−5,−3) is:
DA=
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
=
(1−(−5))
2
+(2−(−3))
2
=
(1+5)
2
+(2+3)
2
=
6
2
+5
2
=
36+25
=
61