Prove that√11 is given as an irrational number
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Step-by-step explanation:
Let us assume that √11 is rational.
so it must be in the form a/b.
√11=a/b
√11b=a
squaring both sides, we get
11b^2= a^2 ----------------- eq. 1
therefore, 11 is the factor of a.
Now,
for any integer c,
let, 11c=a
squaring both sides we get,
121 c^2= a^2 --------------eq. 2
From eq. 1 and 2 we get,
121 c^2= 11b^2
11c^2=b^2
so 11 is the factor of b.
so a and b are factors of each other.
But if they would be rational, they should not be the factor.
so, √11 is irrational.
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