prove that✓11is a rational number by the method of contradiction
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By the method of contradiction..
Let √11 be rational , then there should exist √11=p/q ,where p & q are co-primes and q≠0(by the definition of rational number). So,
√11= p/q
On squaring both side, we get,
11= p²/q² or,
11q² = p². …………….eqñ (i)
Since , 11q² = p² so ,11 divides p² & 11 divides p
Let 11 divides p for some integer c ,
so ,
p= 11c
On putting this value in eqñ(i) we get,
11q²= 121p²
or, q²= 11p²
So, 11 divides q² for p²
Therefore 11 divides q.
So we get 11 as a common factor of p & q but we assume that p & q are co-primes so it contradicts our statement. Our supposition is wrong and √11 is irrational.
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