.Prove that: 13−√8-1√8−√7+ 1√7−√6-1√6−√5+ 1√5−2=5
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I'm sure the question must be:
prove that: 1/3-√8-1/√8-√7+1/√7-√6-1/√6-√5+1/√5-2=5
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Now,
1/3-√8 = 3+√8,
1/√8-√7 = √8+√7,
1/√7-√6 = √7+√6,
1/√6-√5 = √6+√5,
1/√5-2 = √5+2
∴ 1/3-√8-1/√8-√7+1/√7-√6-1/√6-√5+1/√5-2
= 3+√8-√8-√7+√7+√6-√6-√5+√5+2
=3+2 = 5
Hence proved.
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