Math, asked by sawantharsh100, 6 months ago

Prove that 16sin theta cos theta cos 2 theta cos 4 theta cos 8 theta = sin 16 theta

Answers

Answered by Gentleman123321

1

Step-by-step explanation:

16sinAcosAcos2Acos4Acos8A

8(2sinAcosA)cos2Acos4Acos8A

2sinBcosB = sin2B

Similarly, further

8sin2Acos2Acos4Acos8A

4sin4Acos4Acos8A

2sin8Acos8A

sin16A

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