Prove that √18 is irrational
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According to the theorem, it follows that √18 is either an integer or an irrational number. Because it is not an integer (for 18 is not a perfect square, i.e. 18 is not the square of an integer), it is irrational. In general, if x is a positive integer, and q√x is not an integer, then it will be irrational.
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