Prove that 1bycosecA-cotA+1/cosecB-cotB+1/cosecC-cotC=cosecA+cosecB+cosecC+cotA+cotB+cotC
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Prove that
1/cosecA-cotA+ 1/cosecB-cotB +1/cosecC-cotC = cosecA + cosecB + cosecC + cotA + cotB + cotC
Proof:
1/cosecA-cotA=1*(cosecA+cotA)/(cosecA+cotA)*(cosecA-cotA)
1/cosecA-cotA=(cosecA+cotA)/(cosec^2A-cot^2A)=cosecA+cotA
and similarly,
1/cosecB-cotB=cosecB+cotB
and again similary,
1/cosecC-cotC=cosecC+cotC
Now add all right hand side terms and we will get,
=cosecA+cotA+cosecB+cotB+cosecC+cotC
1/cosecA-cotA+ 1/cosecB-cotB +1/cosecC cotC=cosecA+cosecB+cosecC+cotA+cotB+cotC
Hence Proved!
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