Math, asked by rchitta1991, 1 year ago

Prove that 1bycosecA-cotA+1/cosecB-cotB+1/cosecC-cotC=cosecA+cosecB+cosecC+cotA+cotB+cotC
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Answers

Answered by misbahsajjid4
14

Prove that

1/cosecA-cotA+ 1/cosecB-cotB +1/cosecC-cotC = cosecA + cosecB + cosecC + cotA  + cotB + cotC

Proof:

1/cosecA-cotA=1*(cosecA+cotA)/(cosecA+cotA)*(cosecA-cotA)

1/cosecA-cotA=(cosecA+cotA)/(cosec^2A-cot^2A)=cosecA+cotA

and similarly,

1/cosecB-cotB=cosecB+cotB

and again similary,

1/cosecC-cotC=cosecC+cotC


Now add all right hand side terms and we will get,

=cosecA+cotA+cosecB+cotB+cosecC+cotC

1/cosecA-cotA+ 1/cosecB-cotB +1/cosecC cotC=cosecA+cosecB+cosecC+cotA+cotB+cotC

Hence Proved!


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