Question

prove that 1st equation of motion is dimensionally consistent​

Answer 1

Answer:

V=s/t,

where, s is displacement and t is time,

V=L/T, {dimension of s is L and dimension of t is T}

V=LT^-1,

acceleration has dimension LT^-2 because the formula of acceleration is

a=v/t, here v is velocity and t is time,

a=LT^-1/T,

a=LT^-1*T^-1,

a=LT^-2

by putting these dimension in above equation we get,

LT^-1=LT^-1+LT^-2*T,

LT^-1=LT^-1+LT^-1,

LT^-1=2*LT^-2

so we have,

LT^-1=LT^-1,

=0

Explanation:

pls mark me as brainliest and follow for more great answers