Question

prove that (2,1),(3,4),(-3,6) are the vertices of a right triangle

Answer 1

Answer:

Let A(2,1) B(3,4) c(-3,6)

by Pythagoras theorem , we know (hypo)^2= (perpendicular)^2 + (base)^2  

AB  =√{(6-3)²+(4-6)²} = √{3²+ (-2)²}=√(9+4)=√15 units

BC= √{(-1-6)²+(3-4)²}=√{49+1}=√50 units

CA=√{(3-(-1))² +(6-3)²}=√(16+9)=√25 units  

Then by applying pythagorum theorem we can prove this