Prove that 2^10+5^12 is a composite number.
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Step-by-step explanation:
10+512=(53)4+4(22)4=1254+4⋅44
And then the result follows from Sophie Germain's identity, ie,
a4+4b4=(a2+2ab+2b2)(a2−2ab+2b2)
Yielding,
210+512=(56+103+25)(56−103+25)=16657⋅14657
hope this helps
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