prove that √2 + √10 is irrational number
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Assume that √10 is rational. Therefore √10 = a/b where a and b are coprime integers. Then: √10 = a/b 10 = a^2/b^2 10b^2 = a^2 2*(5b^2) = a^2 Since a^2 is a multiple of 2, a must also be a multiple of 2 (if you square an even number, you get an even number, but if you square an odd number, you get an odd number).29-Jun-2016
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