Question

Prove that:
(2^2n-3.2^2n-2)(3^n-2.3n-2)/3^n-4(4^n+3-2^2n

Answer 1

2^2n + 2^2n + 2^2n + 2^2n = 4^24

=> 4 x 2^2n = 4^24 = 2^48

=> 2^2 x 2^2n = 2^48

=> 2^(2n+2) = 2^48

=> 2n+2 = 48=> n =23