prove that (2,-3)( -1,-2) (0,1) (3,0) are the vertices of a rhombus
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Answer:
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Step-by-step explanation:
Diagonal of AC=√(x2-x1)2+(y2-y1)2
=√(3-2)2+(0-{-3})2
=√2+6
=√8
=2√2
diagonal of BD=√(x2-x1)2+(y2-y1)2
=√(0-{-1})2 +(1-{-2})2
=√(1)+9
=√10
=2√5
Area of rhombus=1/2(product of it's diagonal)
=1/2×2√5×2√2
=2√10
=2×3.162
=6.32 unit
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