Question

Prove that (2√3 -1) is an irrational number.​

Answer 1

Step-by-step explanation:

If a/b=sqrt(6), then a2=6b2

On the other hand, given integers ''a'' and ''b'', because the valuation (i.e., highest power of 2 dividing a number) of 6b2 is odd, while the valuation of a2 is even, they must be distinct integers. Contradiction