Prove that: (2 − 3)²− (2 + 3)² +24xy = 0
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Answer:
(2-3)^2-(2+3)^2+24xy=0
Step-by-step explanation:
(
(-1)*(-1)-5*5+24xy=0
1-25+24xy=0
-24+24xy=0
24xy=24
xy=24/24=1
xy=1
put the value of xy=1
(2-3)^2-(2+3)^2+24xy=0
-24+ 24xy=0
-24+ 24*1=0
left=right
prove that
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