Question

prove that (2+3√2)/7 is an irrational number​

Answer 1

Step-by-step-Explanation:

Let us assume that 2+3√2 rational number

(i.e) 2+3√2 =P/q ( Where p,q are positive integer and co prime q is not equal to zero)

3√2= P-3/q

3√2= P-3q/q

√5= P-3q/2q

√5 is irrational number ( Where p and q are integer p-3q/2q is irrational number)

This contact that the fact √2 is irrational numbers

So our assumption answer is incorrect answer

Hence 2+3√2 is irrational number

So i hope this answer will help you dear