prove that 2-3√2 is irrational
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Step-by-step explanation:
Let us assume that √2 + 3 /√2 is irrational number
√2+3/√2=a/b (a and b are co primes
and b not equal to zero)
√2=a/b - 3/√2
or√2=√2a-3b /2b
scenes a and b are integers we get √2a-3b /2b is rational and so root 2 is rational
But this contradicts the fact that √2 is irrational . this contradiction is arise and because of or incorrect assumption that√2 + 3 /√2 is a rational number.
so we conclude that √2 + 3 /√2 is an irational number.
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