prove that √2-3√3 is irrational number
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Step-by-step explanation:
let √2-2√3 be a rational no.
so let √2-2√3 = m
√2 = m - 2√3
(√2)² = (m - 2√3)²
2= m² + 12- 4√3m
4√3m = m² -10
√3= (m² -10)÷4m
as m is rational and m≠0
so, (m² -10)÷4m is rational
but √3 is rational
this contradict our assumption that √3 is irrational
- therefore, √2-3√3 is an irrational number
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