prove that 2- 3√5 is an irrational number
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Step-by-step explanation:
Let 2- 3 * root 5 be the rational no such that 2- 3 root 5 = p/ q where p and q are co - prime integer and q is not equal to 0, 2-3root 5 = p/ q , -3root5 = p/q -2 , -3root 5 = p-2q /q , root 5 = -p+2q/q _ equation no.1 , as p, q are integer therefore -p+2q/q is a ratio of two integer which implies that this is a rational no. From root 5 is a rational no. But it is a contradiction the fact that root 5 is a irrational no.
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