Prove that 2-3√5 is an irrational number.
Answers
Answered by
0
Let x=2−3
5
be a rational number.
3
5
=2−x
5
=
3
2−x
Since x is rational, 2-x is rational and hence
3
2−x
is also rational number
⇒
5
is a rational numbers, which is a contradiction.
Hence 2−3
5
must be an irrational number.
5
be a rational number.
3
5
=2−x
5
=
3
2−x
Since x is rational, 2-x is rational and hence
3
2−x
is also rational number
⇒
5
is a rational numbers, which is a contradiction.
Hence 2−3
5
must be an irrational number.
Answered by
31
Step-by-step explanation:
To prove:-2-3√5 is an irrational no.
Let us assume contrary that 2-3√5 is rational.
Let 2-3√5 where a and b coprime numbers,
b is not Equal to 0
2-a/b=3√5
2b-a/3b=√5
Since a and b are integers ,we get 2b-a/3b is rational,so √5 is irrational .
But ,this condradicts the fact that √5 is irrational,the condradiction has arisen Because of our incorrect assumption that 2-3√5. is rational
So we conclude that 2-3√5 is irrational
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