Math, asked by jothikautilyan, 2 months ago

Prove that 2-3√5 is an irrational number.​

Answers

Answered by Rudra0899
0
Let x=2−3
5

be a rational number.

3
5

=2−x

5

=
3
2−x



Since x is rational, 2-x is rational and hence
3
2−x

is also rational number


5

is a rational numbers, which is a contradiction.

Hence 2−3
5

must be an irrational number.
Answered by PeeyushVerma
31

Step-by-step explanation:

To prove:-2-3√5 is an irrational no.

Let us assume contrary that 2-3√5 is rational.

Let 2-3√5 where a and b coprime numbers,

b is not Equal to 0

2-a/b=3√5

2b-a/3b=√5

Since a and b are integers ,we get 2b-a/3b is rational,so √5 is irrational .

But ,this condradicts the fact that √5 is irrational,the condradiction has arisen Because of our incorrect assumption that 2-3√5. is rational

So we conclude that 2-3√5 is irrational

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