Question

prove that 2√3/5 is an irrational number​

Answer 1

Answer:

therefore it can be written in form of a and b where a and b are co-prime numbers. 5a/b is rational number as it is of the form p/q which is a rational number. but we know that √3 is irrational number so our assumption is wrong. 2√3/5 is irrational.

Answer 2

Answer:

Given: 3 + 2√5

To prove: 3 + 2√5 is an irrational number.

Proof:

Let us assume that 3 + 2√5 is a rational number.

So, it can be written in the form a/b

3 + 2√5 = a/b

Here a and b are coprime numbers and b ≠ 0

Solving 3 + 2√5 = a/b we get,

=>2√5 = a/b – 3

=>2√5 = (a-3b)/b

=>√5 = (a-3b)/2b

This shows (a-3b)/2b is a rational number. But we know that √5 is an irrational number.

So, it contradicts our assumption. Our assumption of 3 + 2√5 is a rational number is incorrect.

3 + 2√5 is an irrational number

Hence proved

well it's same as this one

pls mark brainliest