Prove that 2+√3/5 is an irrational number, given that √3 is an irrational number.
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Let the 2+root3 root 5 be a rational no.
Therefore it can be written in form of p/q (q not =0 and p, q are co. Prime)
2+......=p/q
Root 3 root 5=p/q - 2
Root 3=1/root(p/q-2)
Here in lhs root 3 is irrational and in RHS all the no. Are rational....hence our supposition is wrong.. It is contradict to fact that the root3 is irrational and a rational no. Can't be equal to the irrational..
So the given no...... Is irrational.
Therefore it can be written in form of p/q (q not =0 and p, q are co. Prime)
2+......=p/q
Root 3 root 5=p/q - 2
Root 3=1/root(p/q-2)
Here in lhs root 3 is irrational and in RHS all the no. Are rational....hence our supposition is wrong.. It is contradict to fact that the root3 is irrational and a rational no. Can't be equal to the irrational..
So the given no...... Is irrational.
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