Question

Prove
that
2-3√5
is irrational​

Answer 1

Assume 2-3√5 be a rational no

therefore 2-3√5=a/b

hence √5=a-2b/3b

therefore a-2b/3b is a rational no

therefore √5 is a rational no

but we know that √5 is a irrational no

therefore our assumption was wrong that 2-3√5 is a rational no

therefore 2-3√5 is a irrational no

Answer 2

Answer:

-3√5 = - 2

√5 = 2 /3

we know that root 5 is irrational

and 2 / 3 is rational

so irrational not equal to rational

therefore the give number is irrational

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