Question

prove that 2√3-7 is irrational ​

Answer 1

Step-by-step explanation:

let us assume that

let us assume that 2 root 3-7 is a rational no.

so, 2 root 3-7 = p/q ( where p and q are some integers and q # 0

=> root 3 = p-7q /2q

this shows that root 3 is rational no. (because p, q ,7 and 2 are some integers )

but we know that root 3 is irrational no.

This contadicts our assumption

=> 2 root 3 -7 is irrational no.