Question

Prove that 2√3 and 2√3-4 are irrational numbers

Answer 1

Answer:

$2 \sqrt{3}$

Step-by-step explanation:

let assum that 2root 3is an rational number .

$2 \sqrt{3} = \frac{p}{q}$

$\sqrt{3} = \frac{p}{2q} - - - -1$

$from {eq}^{n} 1$

RHS is rational &

LHS is irrational number

which is contradiction.

our assumption is wrong.

$2 \sqrt{3} is \: a \: irrational$

like this we can solve the another examples