Question

prove that 2√3 by 5 is irrational​

Answer 1

Step-by-step explanation:

1. let us assume 2route3by 5 be a rational no.such that 2route3by t=abyb

Answer 2

$\textbf{\large{\pink{\underline{\underline{Step by step Explanation:-}}}}}$

$\textit{\underline{Suppose that,,}}$

$\mathit{7\sqrt{5}=\frac{p}{q}}$ is a rational number and both $\mathrm{'p',,and,,'q'}$ are integers and $\mathrm{b\ne 0.}$

$\textit{\underline{Hence,,}}$

$\mathit{7\sqrt{5}=\frac{p}{q}}$

$\mathit{\implies{\sqrt{5}=\frac{p}{7q}}}$___(1)

Because,'p',,7 and 'q' are integers.Hence ($\math</strong><strong>i</strong><strong>t</strong><strong>{\frac{p}{7q}}$) is a rational number.Hence,, according to (1),,($\mathrm{\sqrt{5}}$) is also a rational number Which is paradox. So,,our believing is wrong.

$\textit{\underline{Hence,,}}$

$\mathrm{7\sqrt{5}}$ is an irrational number.

✌️✌️$\textit{\underline{Hence proved,,}}$✌️✌️

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