prove that 2√3 divided by 5 is irrational step by step
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Step-by-step explanation:
Let 2root 3 / 5 be a rational no. in the form a/b where, a and b are integers.
Now,
2root3 / 5 = a / b
2root3 = 5a / b
root3 = 5a / 2b
Here. since a/b is a rational no., so 5a / 2b is also a rational no.
Hereby, root3 should also be a rational no.
But this contradicts tha fact that root3 is a rational no.
So, our assumption is wrong and hence 2root3 / 5 is an irrational no.
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