Prove that 2 = 3(do not do 2*0 = 3*0 please)
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Answer:
Let 2 equation be x³+x²+3x=0 & x³+x²+2x=0.
Put x=0 in both equation to prove LHS=RHS.
NOW, take first equation x³+x²+3x=0, x³+x²+2x=0.
Now take x common from both the equations.
x²+x+3=0, x²+x+2=0.
Both equations are equal to zero. So we can make both equation equal.
x²+x+3=x²+x+2
x²+x-x²-x+3=2
So, 3=2
HENCE PROVED
Step-by-step explanation:
Answered by
1
Let 2 equation be x³+x²+3x=0 & x³+x²+2x=0.
Put x=0 in both equation to prove LHS=RHS.
NOW, take first equation x³+x²+3x=0, x³+x²+2x=0.
Now take x common from both the equations.
x²+x+3=0, x²+x+2=0.
Both equations are equal to zero. So we can make both equation equal.
x²+x+3=x²+x+2
x²+x-x²-x+3=2
So, 3=2
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