prove that √2 + √3 is an irrational no
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Heya!
Here is yr answer......
Let us assume √2+√3 is rational
let √2+√3 = a/b [ a, b are any two integers]
=> √3 = a/b-√2
by squaring on both sides......
=> 9 = a²/b²+2-2(a/b)(√2)
=> 9 = a²/b²+2-2√2a/b
=> 2√2a/b = a²/b²+2-9
=> 2√2a/b = a²/b²-7
=> 2√2a/b = a²-7b²/b²
=> 2√2a = a²-7b²/b
=> √2 = a²-7b²/2ab
For any two integers RHS (a²-7b²/2ab) is rational
But, LHS(√2) is irrational.
A rational and irrational are never equal.!
So, assumption is false
Therefore, √2+√3 is irrational
Hope it hlpz..
Here is yr answer......
Let us assume √2+√3 is rational
let √2+√3 = a/b [ a, b are any two integers]
=> √3 = a/b-√2
by squaring on both sides......
=> 9 = a²/b²+2-2(a/b)(√2)
=> 9 = a²/b²+2-2√2a/b
=> 2√2a/b = a²/b²+2-9
=> 2√2a/b = a²/b²-7
=> 2√2a/b = a²-7b²/b²
=> 2√2a = a²-7b²/b
=> √2 = a²-7b²/2ab
For any two integers RHS (a²-7b²/2ab) is rational
But, LHS(√2) is irrational.
A rational and irrational are never equal.!
So, assumption is false
Therefore, √2+√3 is irrational
Hope it hlpz..
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